(4/x+2)+(1/x)=(-7/x^2-4)

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Solution for (4/x+2)+(1/x)=(-7/x^2-4) equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4/x+1/x+2 = -7/(x^2)-4 // + -7/(x^2)-4

4/x+1/x-(-7/(x^2))+2+4 = 0

4/x+1/x+7*x^-2+2+4 = 0

5*x^-1+7*x^-2+6 = 0

t_1 = x^-1

7*t_1^2+5*t_1^1+6 = 0

7*t_1^2+5*t_1+6 = 0

DELTA = 5^2-(4*6*7)

DELTA = -143

DELTA < 0

x belongs to the empty set

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